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Unit 16: The Grid

Where geometry meets algebra.

Unit 16 of 28 in Problem-solving maths for kids. Its 7 lessons are Naming a Point, How Far Apart, Shapes on the Grid, Reading a Straight Line, Working Out the Shape, Steepness on the Grid and Lines and Their Steepness — below is everything each one explains, and a question or two from it to try.

The answers are marked in the app by value — 1/2, 0.5 and 2/4 all count — and every one is re-derived by sympy before it ships.

This unit opens with a fortnight’s trial of everything — no card needed — or with a family plan, bought in the iPhone app. The first two units of every track are free for ever. Try it in the app.

📍 Naming a Point

Two numbers find any spot

Draw two number lines crossing at right angles. Now every point on the page has an address: along first, then up.

The point (3, 2) is 3 along and 2 up. The point (2, 3) is somewhere else entirely — the order matters.

Where they cross is (0, 0), called the origin.

Four quarters

Go left of the origin and the first number is negative. Go below it and the second is.

So (-4, 3) is four to the left and three up, and (2, -5) is two right and five down.

The two lines cut the page into four quadrants, and the signs tell you which one you are in.

The midpoint is the average

To find the point exactly halfway between two others, average each number separately.

Halfway between (2, 3) and (8, 7) is ((2+8)/2, (3+7)/2), which is (5, 5).

That is all a midpoint is: the average of the two addresses.

Try it yourself

Which point is 5 along and 1 up?

  • (5, 1)
  • (1, 5)
  • (5, 5)
  • (6, 0)

Where is the point (-3, -2)?

  • Left and below the origin
  • Left and above
  • Right and below
  • On the origin

Answer them in the app

📏 How Far Apart

Pythagoras on the grid

To find the distance between two points, draw the right-angled triangle underneath them.

The across side is the difference of the first numbers. The up side is the difference of the second. Then Pythagoras finishes it.

From (1, 2) to (4, 6): across 3, up 4, so the distance is sqrt(9 + 16) = 5.

Try it yourself

How far is it from (0, 0) to (6, 8)?

How far is it from (2, 3) to (7, 15)?

Answer them in the app

🔷 Shapes on the Grid

A shape is just a list of points

Give four points and you have described a quadrilateral exactly — no drawing needed, no measuring, no argument about whether it looks right.

(0,0), (4,0), (4,3), (0,3) is a rectangle 4 across and 3 up. Anybody in the world would draw the same one.

That precision is the whole gift of coordinates.

Vertical and horizontal lengths are subtractions

The distance between (2, 1) and (2, 7) is simply 7 - 1 = 6. They share a first number, so the line is straight up.

Likewise (3, 5) to (11, 5) is 11 - 3 = 8.

Only when both numbers change do you need Pythagoras. Checking for a shared number first saves a lot of work.

Try it yourself

A rectangle has corners (0,0), (4,0), (4,3) and (0,3). What is its perimeter?

What is that rectangle’s area?

Answer them in the app

📉 Reading a Straight Line

A rule makes a table, a table makes a line

Take the rule y = 2x + 1. Feed in some values of x and see what comes out.

x = 0 gives 1. x = 1 gives 3. x = 2 gives 5. x = 3 gives 7.

Plot (0,1), (1,3), (2,5), (3,7) and they line up perfectly straight. Every rule with no powers in it does that.

Flat lines and upright ones

Two special cases are worth knowing before the general one.

y = 4 is a horizontal line: whatever x does, y stays at 4.

x = 4 is a vertical line: x never moves, and y can be anything.

They look similar written down and are at right angles on the page, so it is worth pausing over which is which.

Try it yourself

For y = 2x + 1, what is y when x is 5?

For y = 4x - 3, what is y when x is 0?

Answer them in the app

🧭 Working Out the Shape

Proving, not guessing

Is the triangle with corners (0,0), (6,0) and (3,4) isosceles?

Measure with Pythagoras. The two slanted sides are both sqrt(9 + 16) = 5. The base is 6.

Two sides equal, so yes — and you have proved it rather than squinting at a drawing.

The midpoint proves things too

To show a quadrilateral is a parallelogram, check whether its diagonals share a midpoint.

For corners (0,0), (5,1), (7,5) and (2,4): one diagonal runs (0,0) to (7,5), midpoint (3.5, 2.5). The other runs (5,1) to (2,4), midpoint (3.5, 2.5).

The same point. So the diagonals bisect each other, and by unit 12 it is a parallelogram.

Try it yourself

How far is it from (0, 0) to (3, 4)?

How far is it from (6, 0) to (3, 4)?

Answer them in the app

⛰️ Steepness on the Grid

Rise over run

How steep is a line? Count how far it climbs, and divide by how far it travels sideways.

From (1, 2) to (5, 10): it climbs 8 over a run of 4, so the gradient is 2. For every one step right, it goes two up.

That single number describes the whole line, because a straight line has the same steepness everywhere.

Flat is zero, upright has none at all

A horizontal line climbs nothing, so its gradient is 0.

A vertical line runs nowhere sideways, so the calculation would divide by zero. Its gradient is undefined — not infinity, not zero, simply not a number.

That is why y = mx + c cannot describe a vertical line. There is no m that would work.

Try it yourself

What is the gradient of the line through (1, 2) and (5, 10)?

What is the gradient of the line through (0, 3) and (4, 15)?

Answer them in the app

📈 Lines and Their Steepness

Gradient: up divided by along

The gradient of a line is how much it climbs for every one step to the right.

From (1, 2) to (4, 8) it climbs 6 over a run of 3, so the gradient is 6/3 = 2.

A line going downhill has a negative gradient. A flat line has gradient 0.

The equation of a line

Every straight line can be written y = mx + c.

m is the gradient, and c is where it crosses the up-line — the intercept.

So y = 3x + 2 climbs 3 for every 1 across, and passes through (0, 2). Read it off, no working needed.

Parallel and perpendicular

Two lines are parallel when their gradients are equal — same steepness, never meeting.

They are perpendicular when the gradients multiply to -1. So a line of gradient 2 crosses at right angles to one of gradient -1/2.

Flip it over, change the sign. That is the whole rule.

Try it yourself

What is the gradient of the line through (0, 1) and (5, 11)?

What is the gradient of the line through (2, 9) and (6, 1)?

Answer them in the app